Constructions and proofs: explain why the picture must work
Before you start: Recognise points, segments, circles and equal lengths.
What the ideal tools are allowed to do
A straightedge draws a straight line through two given distinct points; it has no ruler marks. A compass draws a circle with a chosen centre and radius. Every point on a circle has the same distance from its centre. A screen drawing approximates these objects, but a proof concerns the ideal geometry.
Worked construction: an equilateral triangle on AB
Start with distinct points A and B. Draw a circle centred at A through B, so its radius is AB. Draw another centred at B through A, with radius BA. Choose an intersection C of the circles and join A to C and B to C.
Because C lies on the first circle, AC = AB. Because C lies on the second, BC = BA. Also AB and BA name the same length. Hence AC = AB = BC: all three sides are equal, so triangle ABC is equilateral. These equalities justify the construction; measuring three nearly equal screen distances would only provide approximate evidence.
Assumptions, definitions and deductions
A definition explains a term, such as “equilateral.” A postulate is an accepted starting condition. A deduction follows from those conditions and previously established results. Euclid's early postulates allow joining points, extending segments and drawing circles; the proof also relies on the circles intersecting, a continuity assumption made explicit in modern treatments.
In Euclidean plane geometry, the parallel postulate can be stated as: through a point outside a line, exactly one parallel line passes. Other geometries use different assumptions. A diagram alone cannot settle which assumptions describe a particular mathematical space.
Common mistakes to avoid
Do not infer that a segment is a midpoint or an angle is 90° simply because it looks that way. Identify the construction step or theorem that establishes it. Also keep A and B distinct: a zero-length starting segment does not produce this triangle.
Try it yourself
In the construction, suppose AC = AB has been established. What additional equality proves that BC has the same length?
Show answer and explanation
C lies on the circle centred at B through A, so BC = BA. Since BA = AB, BC equals the same common length as AC.
Use the activity to check your understanding
Construct first, then give a reason for each equality. Use the proof activities to distinguish a visual guess from a deduction.